Cystic Fibrosis in relation to Genetic Equilibrium...

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LiL Homie
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Cystic Fibrosis in relation to Genetic Equilibrium...

Post by LiL Homie » Thu Feb 15, 2007 6:18 am

Cystic fibrosis is a genetic disease of humans caused by homozygosity for a recessive gene called the gene "a". In a particular large population, the newborns affected with cystic fibrosis is 1 in 3,600. In this population what proportion of the population can be expected to be carriers of this trait (heterozygous)?
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Please help me, I've done 8 other problems but this is a more complex one, and I don't know how to go about doing this. Can someone please help explain this to me?
I know the formulas are: p+q= 1 & pp+2pq+qq=1 but Idk how to incorporate the facts I'm given with this... and how am I supposed to get a proportion? I would appreciate the help, thank you so much! = )

* IF i did this right, I got .0328 = Heterozygous... how do I make a proportion though?

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dipjyoti
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Post by dipjyoti » Thu Feb 15, 2007 9:03 am

For details on CFTR: The Gene Associated with Cystic Fibrosis log on to http://www.ornl.gov/sci/techresources/H ... cftr.shtml

About Cystic Fibrosis http://www.genome.gov/10001213

Thank You.

Dip Jyoti Chakraborty
Attachments
chrom7.gif
Approximate gene location is based on Chromosome 7 map from NCBI Entrez Map Viewer.
From, Human Genome Gateway
chrom7.gif (3.51 KiB) Viewed 1399 times
CFTREnglFig3.jpg
Classification of mutations of CFTR gene, by Welsh & Smith, 1993 - Pascale Fanen

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