Discussion of all aspects of cellular structure, physiology and communication.

Moderators: honeev, Leonid, amiradm, BioTeam

Post Reply
Posts: 1
Joined: Wed Nov 15, 2006 2:46 am


Post by wrahma1 » Wed Nov 15, 2006 2:51 am

i recently conducted an experiment testing the effects of pH of three sugars (glucose, sucrose, lactose) on carbon dioxide production rates (i.e. rate of fermentation). the pH levels tested were 3, 7 and 11 respectively (for each sugar, therefore nine experiments were carried out). In all three sugars, the rate of carbon dioxide was highest at pH 7, lowest at pH 11. I am reallllly having difficulty explaining why that is. I know that the optimal pH of enzymes is from 6.5 to 7.5. He told us to explain this biologically, from perspective of enzyme catalyzed reaction and i seriously have no clue where to start explaining. ive been looking for info on this for hours. any help would be greatly appreciated!

User avatar
Inland Taipan
Inland Taipan
Posts: 6832
Joined: Thu Mar 03, 2005 10:18 pm
Location: Romania(small and unimportant country)

Post by MrMistery » Thu Nov 16, 2006 5:58 pm

well, seems you already know the answer. the optimal pH for the activity of glycolysis enzymes is 7, and obviously it is not uniform. think of it as a curve, with the peak at 7, and which is more steep in the basic side than in the acidic side. the reason it evolved to tolerate a slight acidic pH better than a slight basic pH is probably because the organism itself produces some acid even when placed in pH 7, so it "evolved used to pH a little lower than 7". however, there is evolutionary reason why an enzyme active in a basic environment would be favorable in these conditions..
Hope it is clear now
"As a biologist, I firmly believe that when you're dead, you're dead. Except for what you live behind in history. That's the only afterlife" - J. Craig Venter

Post Reply

Who is online

Users browsing this forum: No registered users and 14 guests