here is an easy one for you

Discussion of all aspects of biological molecules, biochemical processes and laboratory procedures in the field.

Moderators: honeev, Leonid, amiradm, BioTeam

Post Reply
oppox
Death Adder
Death Adder
Posts: 96
Joined: Sat May 13, 2006 11:20 am
Location: Sweden

here is an easy one for you

Post by oppox » Thu Oct 19, 2006 10:07 am

Im trying to fully understand this. I got a table with different enzymes and inhibitors.

........x........ y...........z.
1.....0,67.....42........0,17
2.....0,53.....13........0,29


where 1 and 2 are different inhibitors and x, y, z are different enzymes. the figures are Ki (microM). Its been some time ago I read the course covering this so im alittle lost.
Does these result tell me that enzyme x and z are inhibited fairly good whilst
y is not. Is there anything more I can say about these result?
thanks in advance

sdekivit
King Cobra
King Cobra
Posts: 586
Joined: Sat Jul 30, 2005 7:16 pm
Location: holland
Contact:

Post by sdekivit » Thu Oct 19, 2006 8:57 pm

Ki tells you something about the binding affinity for the inhibitor to the enzyme, accoriding to the following equilibrium:

I + E <--> EI with Ki = [E][I]/[EI]

in other words: the lower the Ki, the higher the affinity of the inihibitor to the enzyme.

So indeed: enzyme x and z are potent target of the inhibitors 1 and 2.

oppox
Death Adder
Death Adder
Posts: 96
Joined: Sat May 13, 2006 11:20 am
Location: Sweden

Post by oppox » Thu Oct 19, 2006 11:19 pm

Then I was thinking in the right direction, thank you for making it more clear.

Post Reply

Who is online

Users browsing this forum: No registered users and 7 guests