## calculation problem

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### calculation problem

The following reaction occur in glycolysis.

Fructose-6-phosphate --> glucose-6-phosphate K’ = 1.97

What is the ΔG for the reaction at 25 C.

If the concentration of fructose-6-phosphate is 1.5 M and the concentration of glucose-6-phosphate is 0.5 M, what is ΔG?

(R=8.315 J/mol K)

Explain ΔG0 and ΔG are different?

can anyone show me how to solve this??

Fructose-6-phosphate --> glucose-6-phosphate K’ = 1.97

What is the ΔG for the reaction at 25 C.

If the concentration of fructose-6-phosphate is 1.5 M and the concentration of glucose-6-phosphate is 0.5 M, what is ΔG?

(R=8.315 J/mol K)

Explain ΔG0 and ΔG are different?

can anyone show me how to solve this??

dude i think this is ur home work any how i can just give u a hint ant the name of book to reffer

hints:

1 . search for one standard equation that relates G and G0

2 , its famous name is gibbs equation for entrophy

books:

leninger

voit& voit

more than sufisient

or any bioenergitics or biochemistry or even thermodynamics book wil do all the values r been given subtitute to get the answer

hints:

1 . search for one standard equation that relates G and G0

2 , its famous name is gibbs equation for entrophy

books:

leninger

voit& voit

more than sufisient

or any bioenergitics or biochemistry or even thermodynamics book wil do all the values r been given subtitute to get the answer

the organisms that survive r not the one which r strongest nor the one which r briliant THEY R THE ONE WHICH RESPOND TO CHANGES IN NATURE FIRST

### Re: calculation problem

kabuto wrote:The following reaction occur in glycolysis.

Fructose-6-phosphate --> glucose-6-phosphate K’ = 1.97

What is the ΔG for the reaction at 25 C.

If the concentration of fructose-6-phosphate is 1.5 M and the concentration of glucose-6-phosphate is 0.5 M, what is ΔG?

(R=8.315 J/mol K)

Explain ΔG0 and ΔG are different?

can anyone show me how to solve this??

delta G = delta G(0) + RT ln [glucose-6-phosphate]/[fructose-6-phosphate]

delta G(0) is the standard Gibbs free energy under standard conditions and is therefore different delta G which isn't under standard conditions.

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