Hardy-Weinberg Problems II

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Hardy-Weinberg Problems II

Post by bionewbie » Thu Feb 02, 2006 8:08 pm

Sorry, I have another question

The B allele for brown eyes is dominant to b allele for blue eyes. Allele B has a frequency of 0.2. Given HW-equilibrium, and no differences in allele frequencies between genders, what is the probability that a blue-eyes woman will marry a brown-eyed man?

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Inland Taipan
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Post by MrMistery » Thu Feb 02, 2006 8:17 pm

Depends if they marry for love, money, green card, pancmictic etc.. :lol:
Last edited by MrMistery on Fri Feb 03, 2006 12:50 pm, edited 1 time in total.
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King Cobra
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Post by 2810712 » Fri Feb 03, 2006 10:00 am

the random mating is implied when there is HW-equilibrium.
-Use binomial to get the fraction of population belonging to BB, Bb and bb.
-find out the no. of possible pairs,
then find out how many of these are of required type [ here blue eyeF* brown eyeM].Their fraction is nothing but the probability required.

The % n of females/ males in the population will not matter here becuase the pairing is biased i.e. all the pairs aree FM not other types are considered.

Actually the ans. would be genotype frequency of bb*genotype frequency of BB + Bb.


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Post by Dr.Stein » Fri Feb 03, 2006 10:21 am

MrMistery wrote:Depends if they marry for love, money, green card, cancmictic etc.. :lol:

Ahahahhahaahhahaaaaaaa :lol: :lol: :lol: :lol: :lol: :lol: :lol: :lol: :lol: :lol: :lol: :lol: Bad boy!

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