Hardy-Weinberg Problem I

Genetics as it applies to evolution, molecular biology, and medical aspects.

Moderators: honeev, Leonid, amiradm, BioTeam

Post Reply
bionewbie
Coral
Coral
Posts: 113
Joined: Sun Nov 07, 2004 9:54 pm

Hardy-Weinberg Problem I

Post by bionewbie » Thu Feb 02, 2006 3:23 pm

Given two equal size populations that are both in Hardy-Weinberg equillibrium.

Population A p=0.4 q=0.6
Population B p=0.8 q=0.2

What would the expected frequency of heterozygous if these populations were combined into a single population?

User avatar
MrMistery
Inland Taipan
Inland Taipan
Posts: 6832
Joined: Thu Mar 03, 2005 10:18 pm
Location: Romania(small and unimportant country)
Contact:

Post by MrMistery » Thu Feb 02, 2006 7:54 pm

Well, from what i can imagine all you have to do is add them and then divide by 2:
p=(0.4+0.8)/2= 0.6
q=(0.6+0.2)/2= 0.4

From there, it's math

Hope i am right..
"As a biologist, I firmly believe that when you're dead, you're dead. Except for what you live behind in history. That's the only afterlife" - J. Craig Venter

2810712
King Cobra
King Cobra
Posts: 697
Joined: Thu Jan 20, 2005 12:19 pm

Post by 2810712 » Fri Feb 03, 2006 10:09 am

If the pops are mixed before breeding season-
Answer=[pA/2*qA/2+ pB/2*qB/2 + pA/2*qB/2 + pB/2*qA/2]

If pops are mixed after breeding season-
Answer=[pA/2*qA/2+ pB/2*qB/2 ]


pA= allele freq. of p in A similarly qA, pB, qB.






hrushikesh
Last edited by 2810712 on Mon Feb 06, 2006 2:03 am, edited 4 times in total.

User avatar
Dr.Stein
King Cobra
King Cobra
Posts: 3501
Joined: Thu Jul 07, 2005 7:58 am
Location: 55284 Yogyakarta, Indonesia
Contact:

Post by Dr.Stein » Fri Feb 03, 2006 10:20 am

Duh, I hate numbers... Can't help, sorry :oops:
Image

sdekivit
King Cobra
King Cobra
Posts: 586
Joined: Sat Jul 30, 2005 7:16 pm
Location: holland
Contact:

Re: Hardy-Weinberg Problem I

Post by sdekivit » Sat Feb 04, 2006 1:17 pm

bionewbie wrote:Given two equal size populations that are both in Hardy-Weinberg equillibrium.

Population A p=0.4 q=0.6
Population B p=0.8 q=0.2

What would the expected frequency of heterozygous if these populations were combined into a single population?


if we assume population A eand B to count 100 organisms, then te new allel frequency for p will be:

120/200 = 0,6 and q: 80/200 = 0,4

--> thus heterozygous: 2 * 0,6 * 0,4 = 0,48 = 48%

2810712
King Cobra
King Cobra
Posts: 697
Joined: Thu Jan 20, 2005 12:19 pm

Post by 2810712 » Mon Feb 06, 2006 5:07 pm

Please have a review of my edited message and tell ur opinions...



hrushikesh

Post Reply

Who is online

Users browsing this forum: Baidu [Spider], Google [Bot] and 2 guests