Genetics as it applies to evolution, molecular biology, and medical aspects.
sdekivit wrote:Enzyme wrote:xnabizkox wrote:GgTt x GgTt
[GT] _ GGTT _ GGTt _ GgTT _ GgTt
[Gt] _GGTt___ GGtt__ GgTt__ Ggtt
[gT] _ GgTT _GgTt _ ggTT __ ggTt
[gt] __GgTt___ Ggtt__ ggTt __ggtt
If you want to find the chances for having heterozygous for both treats, the answer would be 4/16 which we can simplify to 1/4. YES, IT IS CORRECT .
with my 'probability-tree': Gg = 1/2 and Tt = 1/2
--> GgTt = 1/2 * 1/2 = 1/4 = 4/16
He he, your 'probability tree' is very nice .
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