Got a questiong that is doing my head in.

Discussion of all aspects of cellular structure, physiology and communication.

Moderators: honeev, Leonid, amiradm, BioTeam

Post Reply
Mag
Garter
Garter
Posts: 5
Joined: Fri Dec 09, 2005 2:15 am

Got a questiong that is doing my head in.

Post by Mag » Fri Dec 09, 2005 2:47 am

Thin sections of adult mouse liver were prepared and the calls stained to show up the chromosomes. In asample of 75 000 cells examined, nine where found to be in the process of mitosis. alculate the length of the cell cycle in liver cells, assuming that mitosis lasts 1 hour.

How on earth am i suppose to work that out?

Babenecro
Garter
Garter
Posts: 2
Joined: Thu Mar 03, 2005 7:25 pm

Post by Babenecro » Fri Dec 09, 2005 1:30 pm

Here is my suggestion: x=% of cells in the mitosis/number of minutes in the mitosis

Geordie Boy
Garter
Garter
Posts: 25
Joined: Thu Nov 03, 2005 4:31 pm

Post by Geordie Boy » Fri Dec 09, 2005 11:14 pm

Thats a dodgy question.

Liver cells are not classed as mitotically active cells in the human body. They can regenerate rapidly if some of the cells have been moved, but in a normal liver, less than 1% of cells are going through the cell cycle.

so i dont think the % of cells found would have any bearing on the length of the cell cycle.

Babenecro
Garter
Garter
Posts: 2
Joined: Thu Mar 03, 2005 7:25 pm

Post by Babenecro » Sat Dec 10, 2005 8:15 am

Actually the formula is: x=number of minutes in the mitosis/% of cells in the mitosis...
We used this formula in plant tests, so GB, yuo´re probably right about the liver cells. They need some kind of stimulus to enter mitosis...

Post Reply

Who is online

Users browsing this forum: No registered users and 11 guests