Hardy-Weinberg equilibrium

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Hardy-Weinberg equilibrium

Post by veerosales » Thu Jan 27, 2011 3:11 am

Hi I need help on this Hardy - Weinberg Equilibrium question.

Within the population of butterflies, the color brown (B) is dominant over the color white (b). And, 40 % of all butterflies are white. Calculate the following

a. The percentage of butteflies in the population that is heterozygous.
b. the frequency of homozygous dominant individuals.

** Really important. Need to know how to do thisss asap. Final test is coming up soon :/

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Post by JackBean » Thu Jan 27, 2011 10:35 am

if there are only two alleles and their frequencies (how many butterflies has that allel from 100 butterflies) are q and p, than you must get
q + p = 1
further, the frequency of one homozygot will be q^2; of the other p^2 and of the heterozygot it is 2qp. Of course, sum of these frequencies must be 1 as well:
q^2 + 2qp + p^2 = 1
so, you know that p^2 = 40% = 0.4 => p = 0.63 (I don't have my calc here, so check it;)
then you know, that q = 0.37

and you're looking for 2qp (heterozygous) and q^2 (dominant homozygous)

Cis or trans? That's what matters.

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