MCQ restriction enzyme calculation

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MCQ restriction enzyme calculation

Post by klapausius » Sun May 02, 2010 5:12 am

many restriction endonucleases used in genetic engineering recognize a sequence of 8 nucleotides in DNA where they cleave the phosphodiester bonds in the duplex backbone. how many such sites do you expect in the human genome if u assume a completely random occurance of all four nucleeotides throughout the genome?

a) about 12,000
b) about 24,000
c) about 120
d) about 1,000,000
e) about 45,500

my guess; e)
4^8 = 65,536
genome: 3.0x10^9 (n) / 65,536 = 45,776 = e)?
Im not sure if my steps are right though

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Post by JackBean » Sun May 02, 2010 6:46 am

I think, I have already posted this one about18358.html :roll:

Cis or trans? That's what matters.

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