Cellular Respiration: yeild Net 6 H2O?

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praisgodrua2j
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Cellular Respiration: yeild Net 6 H2O?

Post by praisgodrua2j » Fri Mar 19, 2010 1:02 pm

I am trying to find the pathway of the H2O with formula C6H12O6 + O2 ----> 6CO2 + 6h2O + energy.

The NADH and FADH of the ETC yeild 12 H2O, and looks like Glycolysis yeilds 2 H2O for a total of 14(?).

In order to get a net gain of 6H2O, there must be 8 H2O used as waste products in cellular respiration.

One member pointed out that the Krebs Cycle uses 4, but I can not account for the other 4 H2O.

So how can we reach a net gain of 6 H2O from the original glucose molecule?
Last edited by JackBean on Fri Mar 19, 2010 4:15 pm, edited 1 time in total.
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