Hardy Weinberg HELP!

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shscatch08
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Hardy Weinberg HELP!

Post by shscatch08 » Sun Feb 01, 2009 2:49 am

So I am in a bio class, and i am so lost on everything! If anyone has any tips for catching up quickly on all of this that would be great!

Here is the problem...

In a class, 27% of the students are PTC tasters (a dominant trait), whereas 63% are non-tasters. (note: the square root of 0.27 = 0.52, the square root of 0.63 = 0.79)

I need to find the frequency of the dominant allele and the recessive allele. I know the formula, but I don't know where to plug things in. HELP! :?

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mith
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Post by mith » Sun Feb 01, 2009 2:55 am

Write out the genotypes, and figure out what the formula means.
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Post by shscatch08 » Sun Feb 01, 2009 3:35 am

I have, but i still don't understand.

I know that...

p= frequency of dominant allele
q= frequency of recessive allele
p^2 = % of homozygous dominant individuals
q^2 = % of homozygous recessive individuals
2pq = % of heterozygous individuals

and... p^2 + 2pq + q^2 = 1 and p + q = 1

I just don't understand how to use the formula.

So.. would the frequency by 27 % for the dominant allele? ( That seems to easy, and I don't understand it...)

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mith
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Post by mith » Sun Feb 01, 2009 4:19 am

The dominant allele is present in both heterozygotes and homozygotes so no, its not that simple.
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Post by alextemplet » Sun Feb 01, 2009 3:38 pm

The formula (p^2, q^2, and 2pq) will tell you the frequency of each genotype. Then figure out which alleles correspond to which genotypes.
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RGoodman
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Re: Hardy Weinberg HELP!

Post by RGoodman » Sun Feb 01, 2009 10:15 pm

hi,

I have a little problem with the question u have posted. are you sure those are the right percentage values. because the square of each, eg. the square of 0.27 = 0.52 (rounded up) and the sqaure of 0.63 = 0.79 (rounded) however both these values add up to give 1.31 which in hardyweinberg should be 1. so your percentages must be wrong to start with. if you need any more help give us a shout and i will happily lend a hand.

Bob

P.S. if u want i can take you through step by step of the calculation.

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Post by alextemplet » Sun Feb 01, 2009 11:34 pm

No, 0.27^2 is 0.0729, and 0.63^2 is 0.3969. 2*0.27*0.63 is 0.3402.
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Re: Hardy Weinberg HELP!

Post by RGoodman » Mon Feb 02, 2009 9:27 am

sorry my bad. was late last night when i was doing that and i hit the wrong buttons on my calculator lol yeah the above post is correct. so just to clarift:

0.27*0.27 or 0.27^2 = 0.0729
0.63*0.63 or 0.63^2 = 0.3969

now you find the square of the above values:

square of 0.0729 = 0.27
square of 0.3969 = 0.63

0.027 + 0.63 = 0.9 (close enough to 1) lol

if the is wrong someone say, but from my understanding this give you the p value and q value. (q = recessive, p = dominant)

P.S. Hope this is right, if not ignore everything lol

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