Calculating % recombination and Mapping distance

Genetics as it applies to evolution, molecular biology, and medical aspects.

Moderators: honeev, Leonid, amiradm, BioTeam

Post Reply
Posts: 1
Joined: Sun Mar 23, 2008 4:12 pm

Calculating % recombination and Mapping distance

Post by gymgrl » Sun Mar 23, 2008 6:12 pm


Im confused on how to caluclate the percent recombination and the the mapping distznce in map units. Heres my problem:

Consider a cross in Neurospora involving two allelles at the same locus,C and c. The following tetrad patterns were observed

CCcc 55
ccCC 40
CcCc 7
cCcC 3
CccC 4
cCCc 5

What is the percent recombination and the approximate distance between the genetic locus and the centromere is?
I can't calcualte my percent recombination because im unsure jof the significant difference. But I clacuated my mapping distance by: Getting the sum of all my numbers which is 114,then I added the 4 smaller numbers and I got 19. Now for my calcualteions

19/114=0.166 then divide by 2 since its two genotpyes that are CC and cc.
which equals 0.083,then I multiply by 100 which give me 8.33 mapp units.

But How do I find my percent recombination from my data?
Are there seperate equations for percent recombination and the mapping distance?
Thank you ttyl

User avatar
Inland Taipan
Inland Taipan
Posts: 5345
Joined: Thu Jan 20, 2005 8:14 pm
Location: Nashville, TN

Post by mith » Sun Mar 23, 2008 8:08 pm

I don't think you should divide by 2, map distance is of total recombinations.
Living one day at a time;
Enjoying one moment at a time;
Accepting hardships as the pathway to peace;

King Cobra
King Cobra
Posts: 635
Joined: Thu Feb 14, 2008 7:40 pm

Post by Cat » Tue Mar 25, 2008 5:39 pm

You calculated everything correctly. 8.33 m.u. is also = to 8.33 % which is recombination frequency (1% RF= 1 m.u.).

Your reasoning is not correct though (unless I misunderstood you). You said “19/114=0.166 then divide by 2 since its two genotypes that are CC and cc.”

0.166… or 16.6% is frequency of crossover during meiosis, but only ½ of the product is recombinant. That is why you have to divide by 2; RF = 1/2 of the frequency of crossover during meiosis in this case.

Post Reply

Who is online

Users browsing this forum: No registered users and 3 guests