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Quadrat

Definition

noun

A square or rectangular plot of land used to mark off at random a physical area to isolate a sample and determine the percentage of vegetation and animals occurring within the marked area.


Supplement

A quadrat is a tool used in ecology for sampling purposes. For instance, a quadrat is placed on ground at random to count the vegetation within the sample.


Word origin: Middle English, a square geometric instrument, rectangular area.


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Field Trip Help

My Biology Class had a field trip the other week. We had to observe different plant species in quadrat sections and transect lines which we set up. We took photos of the different plant species and were later asked in class to identify each plant species however no one ...

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by DanielP
Mon Sep 20, 2010 2:27 am
 
Forum: Ecology
Topic: Field Trip Help
Replies: 7
Views: 5164

Quadrat Sampling: Reliability and Validility

Hello What would need to be done to ensure that a quadrat survey is Reliable and valid. Help is respected and greatly appreciated

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by karn
Sun Dec 06, 2009 10:39 am
 
Forum: Ecology
Topic: Quadrat Sampling: Reliability and Validility
Replies: 2
Views: 3978

Limpet Shell Profile - A Level coursework

... limpet shell shape change? Do any birds prey on Limpets? And what stats test should I use, if my method uses an interrupted belt transect with a quadrat every 5m. Im measuring the height and base width of the limpets. Maybe work out a limpet height : base ratio? I was thinking of correlation ...

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by Frogman
Sun Oct 08, 2006 7:30 pm
 
Forum: Ecology
Topic: Limpet Shell Profile - A Level coursework
Replies: 4
Views: 8961

hardy-weinberg equation

... 100% 4 pigs are 25% (aa 25%) q2=0.25 -------> q=0.5 p + q = 1 ---------->p + 0.5 = 1 -----> p = 0.5 AA (homozygotus) are p2----> 0.5 quadrat = 0.25 = 25% 2Aa (heterozygotus) are 2pq----> 2 x (0.5) x (0.5) = 0.5 = 50% so the equition is: AA + 2Aa + aa = 1 25% + 50% +25% = 1

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by victor
Fri Jun 03, 2005 12:51 pm
 
Forum: Evolution
Topic: Hardy-Weinberg equation?
Replies: 5
Views: 10030

Hardy-Weinberg mechanism of evolution

48% population are dominant H (homozygotic)=0.48= p (quadrat) p=about 0.7 p+q=1 (0.7) + q = 1 q=0.3 then how many Hh? According to the equation= p(quadrat) + 2pq + q(quadrat) so, Hh is 2pq =2x(0.7)x(0.3) =0.42 =about 42%

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by victor
Thu May 26, 2005 1:08 pm
 
Forum: Genetics
Topic: Hardy weinburg equation please HELP!!!!!!!!!!!!!!!!!!!!!!!!!
Replies: 19
Views: 14784
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