Minks

... --> then we get the next crossbreeding of F1: Bb x Bb. This leads to 25% BB, 50% Bb and 25% bb --> thus now you know that of the brown minks (25/75) * 100% = 33,33% = BB and 66,67% = Bb --> we have 47* 0,3333 = 15 homozygous brown minks and thus 32 heterozygous brown minks. --> ...

See entire post

... about 3:1 segregation, you should do the Chi squared test. 5. So, as we have called (A,a) to this gen which controls colour, we say that: - Brown minks have this genotype: A_ (AA or Aa) [Dominant homozygous or heterozygous]. - Silver minks have this genotype: aa [Recesive homozygous]. Did I answered ...

See entire post