Genetics as it applies to evolution, molecular biology, and medical aspects.

Moderator: BioTeam

if 48% of a population carry dominant H gene using hardy weinberg what % have Hh??
thats all the info i have
Last edited by confuzd441 on Wed May 25, 2005 5:24 pm, edited 1 time in total.
confuzd441
Garter

Posts: 3
Joined: Wed May 25, 2005 4:50 pm

p=48
q=52
pq=?
Living one day at a time;
Enjoying one moment at a time;
Accepting hardships as the pathway to peace;
~Niebuhr

mith
Inland Taipan

Posts: 5345
Joined: Thu Jan 20, 2005 8:14 pm
Location: Nashville, TN

yeah i know stupid huh??
i get that q= 0.52 but what nxt??
confuzd441
Garter

Posts: 3
Joined: Wed May 25, 2005 4:50 pm

pq=?
Living one day at a time;
Enjoying one moment at a time;
Accepting hardships as the pathway to peace;
~Niebuhr

mith
Inland Taipan

Posts: 5345
Joined: Thu Jan 20, 2005 8:14 pm
Location: Nashville, TN

### Hardy-Weinberg mechanism of evolution

48% population are dominant H (homozygotic)=0.48= p (quadrat)
p+q=1
(0.7) + q = 1
q=0.3
then how many Hh?
so, Hh is 2pq
=2x(0.7)x(0.3)
=0.42

victor
King Cobra

Posts: 2668
Joined: Sat Apr 30, 2005 12:01 pm
Location: Yogyakarta, Indonesia..

Since this was a homework related question i think mithril was trying to make him get the answer himself... He wasn't succeding much
"As a biologist, I firmly believe that when you're dead, you're dead. Except for what you live behind in history. That's the only afterlife" - J. Craig Venter

MrMistery
Inland Taipan

Posts: 6832
Joined: Thu Mar 03, 2005 10:18 pm
Location: Romania(small and unimportant country)

whoops, just realized I forgot the 2 infront of the pq.
@victor, he said that 48% carry the gene not that they're homozygous for it. i.e. it's allele frequency
Living one day at a time;
Enjoying one moment at a time;
Accepting hardships as the pathway to peace;
~Niebuhr

mith
Inland Taipan

Posts: 5345
Joined: Thu Jan 20, 2005 8:14 pm
Location: Nashville, TN

@mithril
From what i can tell victor is right. Hrady weinberg 101
HH- p*p
Hh-2pq
hh-q*q
So to find out what p is you just need to make the sqare root of 48
Regards
ANdrew
"As a biologist, I firmly believe that when you're dead, you're dead. Except for what you live behind in history. That's the only afterlife" - J. Craig Venter

MrMistery
Inland Taipan

Posts: 6832
Joined: Thu Mar 03, 2005 10:18 pm
Location: Romania(small and unimportant country)

confuzd441 wrote:if 48% of a population carry dominant H gene using hardy weinberg

that just means there are 48% with the H gene, not that 48% are p^2.
Living one day at a time;
Enjoying one moment at a time;
Accepting hardships as the pathway to peace;
~Niebuhr

mith
Inland Taipan

Posts: 5345
Joined: Thu Jan 20, 2005 8:14 pm
Location: Nashville, TN

I think that here p=0.48 alel freq cause p^2 is freq of diseased.
p=0.48,q=1-p,2pq=2*0.48*0.52
correct me if i'm wrong

zami'87.
Coral

Posts: 257
Joined: Sat Mar 05, 2005 6:56 pm
Location: Serbia

Ok guys, here it is:
48% carry H gene. That means that the other 52% do not have the H dominant gene, which means that they are homozygotus recessive. From here we can find out the value of q(the frequence of h recessive gene) since hh=q^2. Using windows calculator we get q=0.7211. Since q+p=1 then p=0.2789.
Now the frequence of Hh heterozygotus is: 2pq=2*0.7211*0.2789=0.4022. So 40,22% of your individuals are heterozygotus.
Sorry i missread it the first time
PS: I hate this populational genetics things, never could stand them!!
Regards,
Andrew
"As a biologist, I firmly believe that when you're dead, you're dead. Except for what you live behind in history. That's the only afterlife" - J. Craig Venter

MrMistery
Inland Taipan

Posts: 6832
Joined: Thu Mar 03, 2005 10:18 pm
Location: Romania(small and unimportant country)

nice job Andrew!
I got 0.4992

zami'87.
Coral

Posts: 257
Joined: Sat Mar 05, 2005 6:56 pm
Location: Serbia

Next

### Who is online

Users browsing this forum: No registered users and 2 guests