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FermentationModerator: BioTeam
4 posts • Page 1 of 1
FermentationI am having trouble fully understanding what fermentation is, i know its an anaerobic type of respiration, meaning it doesn't need oxygen. but i don't get lactic acid fermentation & alcoholic fermentation?
alcoholic vs lactic fermentationsalcoholic fermentation refers to the process that transforms sugar into alcohol and carbonic gas (or view http://www.biology-online.org/dictionar ... rmentation), lactic acid fermentation refers to that process where sugar is converted to lactic acid, or to a mixture of lactic acid and other products ..
or view http://en.wikipedia.org/wiki/Fermentati ... emistry%29 hope this helps ^_^ "Why you care about small things? World very simple place...
World only have two things: Things you can eat and things you no can eat." - Quina Quen (ffix)
Definition (from Brock Biology of Microorganisms, 11th edition, page 571)
Fermentation is an internally balanced oxidation-reduction process in which the fermentable substrate becomes both oxidized and reduced. This definition perfectly describes Lactic Acid/Ethanol Fermentations. ****Lactic acid fermentation**** 1st step (glycolysis): Glucose(0) + 2NAD -> 2Pyruvate(+2) + 2NADH We see that Glucose with oxidation state of 0 was oxidized to 2 Pyruvates with oxidation state +2 losing 4 electrons to 2NAD. By the definition we must have internally balanced redox process, so 4 electrons have to be retaken. ( For glycolysis itself 2NAD have to be regenerated to continue the process). Thus, Pyruvate is reduced to Lactate with oxidation state of 0 ( as glucose ): 2nd step: 2Pyruvate(+2) + 2NADH -> 2Lactate (0) + 2NAD We sum the two reactions: Glucose(0) + 2NAD -> 2Pyruvate(+2) + 2NADH 2Pyruvate(+2) + 2NADH -> 2Lactate (0) + 2NAD --------------------------------------------------------- Glucose(0) -> 2Lactate(0) Thus, there is no net change in oxidation state of organic substrate, i.e. the process is internally balanced. ****Ethanol Fermentation**** 1st step (glycolysis): Glucose(0) + 2NAD -> 2Pyruvate(+2) + 2NADH 2nd step: 2Pyruvate(+2) -> 2CO2(+4) + 2Acetaldehyde(-2) Note, there is no net change in C oxidation state. 3rd step: 2Acetaldehyde(-2) + 2NADH -> 2Ethanol(-4) + 2NAD Now we sum all the reactions: Glucose(0) + 2NAD -> 2Pyruvate(+2) + 2NADH 2Pyruvate(+2) -> 2CO2(+4) + 2Acetaldehyde(-2) 2Acetaldehyde(-2) + 2NADH -> 2Ethanol(-4) + 2NAD ------------------------------------------------------------- Glucose(0) -> 2CO2(+4) + 2Ethanol(-4) Again, we’ve got no net change in oxidation state of C atoms. Note: 1) I've omitted balance for H ions. 2) The problem with the above perfect definition arises when dismutation reaction is used for energy generation. See viewtopic.php?t=8284. Please, someone help to poor student!
4 posts • Page 1 of 1
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