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## Help with Hardy-Weinberg Equation?
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## Help with Hardy-Weinberg Equation?If about 35% of the human population has type "O" blood,
a) What must the frequency of the type O allele? b)what proportion of the populaton must be heterozygous carriers for type O? - lizziezelda
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**Posts:**1**Joined:**Sun May 13, 2012 8:07 pm
## Re: Help with Hardy-Weinberg Equation?We are using the equation p2 + 2pq + q2 = 1, where
p2 = homozygous dominant frequency 2pq = heterozygous frequency q2 = homozygous recessive frequency You should know that blood type O is recessive. Therefore, q2 = .35. Taking the square root of .35 will give you the frequency of the type O allele (q): sqrt (.35) = .592 Therefore, q = .592, and p = .408 (1 - .592) In the Hardy-Weinberg equation, the frequency of heterozygotes is equal to 2pq. Therefore: 2 (.408) (.592) = .483 So, the proportion of the population that are heterozygous carriers is equal to .483 or 48.3%. Sorry for the late reply! I am new to the site! - knorman
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**Posts:**1**Joined:**Fri Jun 08, 2012 5:44 am
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