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## Biology Calculation-is this correct?
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## Biology Calculation-is this correct?Hey just wondering if anyone can tell me whether I have done this calculation right or not.
A baby hamster kidney (BHK) cell has a surface area of 3,400 micrometres². Assume that the endocyte clathrin-coated pits account for 2% of this area and that the surface area of a single coated pit is the same of that of a 100nm diameter clathrin coated vesicle that will be formed from it. If the cell surface has 100,000 transferrin receptors, around 70% are localised within coated pits: work out how many coated pits there are. Ive got: 3,400 * 2% = 68 micrometers(squared) every pit has a 100 nanometer diameter. area of a circle 2*pi*r(squared) 100nanometers=0.1micrometer r=radius 2r=d r=0.05micrometers 2*pi*0.05(squared)=0.0157micromters(squared) 68/0.0157=4329.014 is this correct or would I do pir2 rather than 2*pir2 which would give me an answer of 8658? Or do I need to work out the surface area of a sphere? 4*pi*r2? Please help, thanks BSc (Hons) Forensic Science,
MSc Biological Sciences -
Kezzer - Garter
**Posts:**31**Joined:**Thu Nov 25, 2010 7:20 pm
1) the vesicle is 3D, not 2D
2) why do you calculate two surfaces and divide them? 3) I think you should calaculate the number of the receptors on pits and from that calculate the number of pits. But I think there is missing some info... http://www.biolib.cz/en/main/
Cis or trans? That's what matters. -
JackBean - Inland Taipan
**Posts:**5694**Joined:**Mon Sep 14, 2009 7:12 pm
## Re: Biology Calculation-is this correct?so I need to calculate the surface area of a sphere then, 4*pir(squared)?
I have done the division at the end because they only account for 2% of the total suface area which is 68micrometers squared. The next question is to then calculate how many transferrin receptors there are in each coated pit, but I just can't get my head round how to do that. BSc (Hons) Forensic Science,
MSc Biological Sciences -
Kezzer - Garter
**Posts:**31**Joined:**Thu Nov 25, 2010 7:20 pm
Hey, for the number of transferrin receptors in each coated pit I've got:
100 000 receptors, 70% localised within the coated pits so: 100 000 x 70% = 70 000 receptors in the coated pits. There are 70 000 receptors and 2165 coated pits so: 70 000/2165 = 32 transferrin receptors in each coated pit. Does think look right to anyone? Not very confident when it comes to maths lol Thanks K BSc (Hons) Forensic Science,
MSc Biological Sciences -
Kezzer - Garter
**Posts:**31**Joined:**Thu Nov 25, 2010 7:20 pm
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