Login

|
|
Need help asap! thxModerator: BioTeam
3 posts • Page 1 of 1
Need help asap! thxIn humans, the condition hyperdactyly (possession of twelve fingers) is determined by one gene. When a homozygous normal woman married a man who was homozygous for the condition, all their children had hyperdactyly. If the children were to marry people with the same genotype as them, what is the probability of them having normal children?
can someone pls solve this and give me a DETAILED description! thank you.
if is woman homozygous AA and man aa their children can be only Aa (from mother they always get A and from father they always get a).
If they have children with other people with the same genotype (that is Aa), they will have children AA : Aa : aa in 1 : 2 : 1. http://www.biolib.cz/en/main/
Cis or trans? That's what matters.
3 posts • Page 1 of 1
Who is onlineUsers browsing this forum: No registered users and 0 guests |
© Biology-Online.org. All Rights Reserved. Register | Login | About Us | Contact Us | Link to Us | Disclaimer & Privacy