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Excretory Systems of Fish and Earthworm..

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Excretory Systems of Fish and Earthworm..

Postby aaaaaaaaaa17 » Wed Nov 25, 2009 3:42 am

I had this experiment where i put Fish and worm in tanks of water overnight to provide sample containing their excretory products. Here is the info :

Organism Weight (g) Organism in amount of water (ml) Time (Hours)
Worm 7.3 200 24
Fish 45 6000 24

After 24 hours i calculated the concentration of Ammonia and Urine in the water sample.( I made sure that the original water was ammonia free)

Ammonia (mg/ml/h)
Fish: 8.0246e-3
Worm: 8.3713 e-3

Urea (mg/g)
Fish : 0.015
Worm : 0.00573


Now, the question asks us to come up with a discussion about these results, or to come up with a scientific reason for my answers. I don't know where to start. If someone could point me in the right direction, it would be appreciated.

Billy.
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Postby JackBean » Wed Nov 25, 2009 4:08 am

You have kind of wierd units. Once you use mg/ml*h and the other time you use mg/g?
http://www.biolib.cz/en/main/

Cis or trans? That's what matters.
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Postby aaaaaaaaaa17 » Wed Nov 25, 2009 4:20 am

Sorry, i hope this helps.
Ammonia (mg/ml/h)
Fish: 8.0246e-3
Worm: 8.3713 e-3

Urea (mg/ml/h)
Fish : 0.015
Worm : 0.00573
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Postby JackBean » Wed Nov 25, 2009 4:26 am

Little better...
apparently, in both cases the concentration of amonia is quite similar (but what about the absolute amount?)
That's not the case of urea, which is obviously more concentrated in fish's water (what about the absolute amount?)
http://www.biolib.cz/en/main/

Cis or trans? That's what matters.
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Postby aaaaaaaaaa17 » Wed Nov 25, 2009 4:30 am

Absolute amount? You mean the amount that was already in the water tank?
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Postby jwalin » Wed Nov 25, 2009 5:20 am

how about considering the massess of the 2 organisms
it isn't what you do that matters but it is how you do it
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Postby jwalin » Wed Nov 25, 2009 5:22 am

and how about considering the number of organisms
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Postby jwalin » Wed Nov 25, 2009 5:22 am

don't know how numbers will help
but masses will
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Postby aaaaaaaaaa17 » Wed Nov 25, 2009 5:30 am

well Fish = 45 g in 6000 ml over 24 hours
Worm= 7.3 g in 200 ml over 24 hours

Another information i have is that the fish has an optical density of 0.14 and the worm 0.80.

I hope i was able to provide what was needed.
Thanks
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Postby jwalin » Wed Nov 25, 2009 5:37 am

when i say consider mass.
then 7.3 gm worms produce whatever amounts of urea and ammonia then how much will 45 gm do

use net amount created

i have an idea.
do you know if water content somehow affect the amounts of the substance created. would rather suggest you standardize the weights and amounts of water. and carry out the experinebt again

else do not use conc. and do as i told.



hope that helps
best of luck
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Postby JackBean » Wed Nov 25, 2009 7:23 am

The absolute amount is the total amount (conc.*volume;). Imagine you have 6 l tank or 60 l tank for the fish. The fish will probably produce the same amount in both, right? But concentration will be different, because you have larger volume in second case.

Also, as jwalin suggested, maybe using organism mass or number (fish was maybe 1, but what about worms?) could help as well.
http://www.biolib.cz/en/main/

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Postby mith » Wed Nov 25, 2009 4:17 pm

might also want to measure how much food you fed them
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