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Free drug concentrationModerator: BioTeam
4 posts • Page 1 of 1
Free drug concentrationIf,
Free protein = [(Total protein - Total drug -Dissociation constant)] (+/-) under root of (Total protein - Total drug -Dissociation constant)^2 + 4 (dissociation Constant * Total Protein) divided by 2 If Total protein - 0.035 g /microliter, Total drug - 3319.246 x 10^-15 moles/l (Molecular weight of drug - 337.41 g/mole) Dissociation constant = 0.27 nM, How to calculate the free protein, Above is quadratic equaltion, As the unit dissociation constant of drug is in nM, while that of total protein and total drug is in different units, How to calculate the free protein ? Is there any way to convert 0.27 nM in to some other unit that can be used for calculation? Can any one please help, Thanks in advance.
Re: Free drug concentrationFirst of all, I don't think, you are supposed to substract the diss. const. from the protein amount
What about multiplication? http://www.biolib.cz/en/main/
Cis or trans? That's what matters.
4 posts • Page 1 of 1
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