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## Exponential Growth and Decay
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## Exponential Growth and DecaySo I have been given a couple of questions from my tutor however I have no idea where to start, I'm not asking for the answers just a push in the right direction.
1) 270 Vibrio cholerae cells were inoculated into 10 ml of a liquid culture and incubated for 9 hours. At the end of this time the cells (in a volume of 100 microlitres) were spread onto agar plates and the colony forming units were enumerated after overnight incubation by counting the colonies on plates from different dilutions: e-5 = 643; e-6 = 75; e-7 = 6 Assuming that the cells multiplied by binary fission and the culture was in synchronized exponential growth throughout the incubation, how many full generations did the culture undergo and what was the generation time. I guessed that you can only use one of the counts from the dilutions to perform the calculations and the number should be between 30 and 300 so I guess i'm using the 10^-6 2) 500 microlitres of a solution of a DNA fragment labelled with 32P with an initial activity of 0.4 kBq in 10 ml was needed for an experiment 9 days later. Calculate the radioactivity of the sample used in the experiment (T = half-life) (I think I first need to work out the amount of radioactivity in the sample to be used in the experiment, but couldn't work that one out) 3) Barium-140 has a half light of 13 days. How many decay half-lives does a sample of barium-140 undergo in 6 weeks? What fraction of the sample would remain after 6 weeks? (Confusing question, I guessed barium-140 would go through 3.23 half-lives and that it would be around 1/8th of the sample left over, but exact number eludes me) Last edited by Chemhalp on Wed Apr 23, 2008 7:59 pm, edited 1 time in total.
- Chemhalp
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**Posts:**23**Joined:**Wed Nov 28, 2007 2:22 pm
Amount of original stuff * (1/2)^n = stuff left
where n is number of half lives. You can derive a similar equation for calculating number of half lives. Living one day at a time;
Enjoying one moment at a time; Accepting hardships as the pathway to peace; ~Niebuhr -
mith - Inland Taipan
**Posts:**5345**Joined:**Thu Jan 20, 2005 8:14 pm**Location:**Nashville, TN
## Re: Exponential Growth and DecaySo for question three,
42 days / 13 day half life = 3.23 ergo 0.5^3.23 = 0.106579361, which is fraction of the sample after the 6 weeks? - Chemhalp
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**Posts:**23**Joined:**Wed Nov 28, 2007 2:22 pm
Well does the answer make intuitive sense?
what is happening when you raise 1/2 to a power? You can write out the integer series if it helps. Living one day at a time;
Enjoying one moment at a time; Accepting hardships as the pathway to peace; ~Niebuhr -
mith - Inland Taipan
**Posts:**5345**Joined:**Thu Jan 20, 2005 8:14 pm**Location:**Nashville, TN
http://en.wikipedia.org/wiki/Exponential_growth
If you manipulate the formula a little, its basically what you'll need for exponential stuff. Living one day at a time;
Enjoying one moment at a time; Accepting hardships as the pathway to peace; ~Niebuhr -
mith - Inland Taipan
**Posts:**5345**Joined:**Thu Jan 20, 2005 8:14 pm**Location:**Nashville, TN
## Re: Exponential Growth and DecayOk just had a look at question 1 again...
270 cells in 10ml then 100 microlitres taken So... 10000/100 = 100 so 270/100 = 2.7 So... starting with 27 and ending with 75 is what I have right? original stuff * (1/2)^n = stuff left as you said above So... 2.7 * 0.5^(n) = 75 75/2.7 = 0.5^(n) But that gives me like 0.5^n = 27 which can't be... So then I got thinking that its at dilution e-6 so something else should have been done -_- Any hints? - Chemhalp
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**Posts:**23**Joined:**Wed Nov 28, 2007 2:22 pm
note that when you multiple by 1/2 ^ n , it halves it n times.
In this case you're looking at growth, specifically binary fission so you should be doubling n times i.e. 2^n. Enjoying one moment at a time; Accepting hardships as the pathway to peace; ~Niebuhr -
mith - Inland Taipan
**Posts:**5345**Joined:**Thu Jan 20, 2005 8:14 pm**Location:**Nashville, TN
I'm not quite sure but from the way you wrote it, it seems like this is how it looks
You have a dilution with "x" number of colonies and it multiplied "n" times x* 2^n=6 for the second dilution 10x * 2^n = 75 from third 100x * 2^n =643 But it's impossible to solve for the x or n because all 3 equations are linearly dependent...so I'm not sure what additional information I'm missing... Enjoying one moment at a time; Accepting hardships as the pathway to peace; ~Niebuhr -
mith - Inland Taipan
**Posts:**5345**Joined:**Thu Jan 20, 2005 8:14 pm**Location:**Nashville, TN
or...
75 is the number of colonies and not the number of cells so you have to divide the number of colonies by the dilution factor which was 10^-6 and then x 100 to get the number of cells in 10ml. I got 7.5x10^9. Then ln(7.5x10^9/270) /ln2 = 24.7 so the number of divisions is 24 maybe? - Chemhalp
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**Posts:**23**Joined:**Wed Nov 28, 2007 2:22 pm
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